(x-7)(x-7)=x^2-7x-7x+49

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Solution for (x-7)(x-7)=x^2-7x-7x+49 equation: 



(x-7)(x-7)=x^2-7x-7x+49

We move all terms to the left:

(x-7)(x-7)-(x^2-7x-7x+49)=0

We get rid of parentheses

-x^2+(x-7)(x-7)+7x+7x-49=0

We multiply parentheses ..

-x^2+(+x^2-7x-7x+49)+7x+7x-49=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-7x-7x+49)+14x-49=0

We get rid of parentheses

-1x^2+x^2-7x-7x+14x+49-49=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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